Addition of NaOH on Zn²⁺ ion gives a white ppt. which on addition of excess of NaOH which dissolves. In this solution Zn exists in which of the following form?

Anionic form

Zn^2​++ 2OH^-→ Zn(OH)₂​ (white ppt.).
In excess of NaOH, it dissolves and form complex.
Zn(OH)₂​ + 2OH^- →Zn(OH)₄²⁻​
In this complex, oxidation state of Zn is +2.