If A and B are square matrices of same order, then \(A'B - B'A\) is a:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → Skew symmetric matrix
Let \(P = A'B - B'A\). Take the transpose, using \((XY)' = Y'X'\) and \((X')' = X\):
\(P' = (A'B)' - (B'A)'\)
\(= B'(A')' - A'(B')'\)
\(= B'A - A'B\)
\(= -P\)
A square matrix with \(P' = -P\) is skew symmetric. So A′B − B′A is a skew symmetric matrix.