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Home/Practice questions/Chemistry
ChemistryPhysical: Chemical Kinetics

Match the LIST-I with LIST-II.LIST-I(Condition/ Reaction)LIST-II(Poss…

Match the LIST-I with LIST-II.

LIST-I
(Condition/ Reaction)
LIST-II
(Possibility)
A. Molecularity of reactionI. Can have fractional value
B. Thermal decomposition of HI on gold surfaceII. Not meaningful for complex reaction.
C. Order of reactionIII. First order reaction
D. Radioactive decayIV. Zero order reaction

Choose the correct answer from the options given below:

Answer & explanation+

Correct answer: option 1

The correct answer is Option (1) → A-II, B-IV, C-I, D-III

Order and molecularity are often confused. Order is an experimental quantity: the sum of the powers of the concentration terms in the rate law, so it can be zero, a whole number or a fraction. Molecularity is a theoretical quantity: the number of reacting species that collide in one elementary step, so it is always a whole number (1, 2 or 3).

  • A. Molecularity of reaction — This matches II. Not meaningful for complex reaction. A complex reaction takes place in several elementary steps, each with its own molecularity, so the reaction as a whole has no single molecularity. Its rate is decided by the slowest step.

  • B. Thermal decomposition of HI on gold surface — This matches IV. Zero order reaction. At high pressure the gold surface is fully covered with HI molecules, so adding more HI does not change the rate: the rate is independent of concentration.

        \( \displaystyle \ce{2HI(g)} \xrightarrow{\ce{Au}} \ce{H2(g) + I2(g)},\quad \text{Rate}=k[\ce{HI}]^{0}=k \)

  • C. Order of reaction — This matches I. Can have fractional value. Order comes from the experimental rate law, and the powers in it can be fractions (for example, Rate = k[CH3CHO]3/2).

  • D. Radioactive decay — This matches III. First order reaction. The rate of decay is proportional to the number of nuclei present, which is why every radioactive element has a constant half-life.

        \( \displaystyle \text{Rate}=\lambda N,\quad t_{1/2}=\frac{0.693}{\lambda} \)

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