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Find the value of x and y if \(\begin{bmatrix}3-8x&3\\x-3&-2\end{bmatrix}\) = \(\begin{bmatrix}-5&2y-3\\-2&x-y\end{bmatrix}\) |
x =-1 and y =3 x = 1 and y =-3 x = 1 and y = 3 None of these |
x = 1 and y = 3 |
Equating all the corresponding terms of both the matrices we get 1) 3-8x = -5 i.e., -8x = -8 and is x=1 2) 2y-3 =3 i.e., 2y = 6 and so y=3 |
