Practicing Success
Practicing Success
CUET Preparation Today
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Let electric field is zero at a distane x from q2 charge away from q1. $\frac{K.q_2q}{4\pi \epsilon_0 x^2} = \frac{K q_1q}{4\pi \epsilon_0 (x+d)^2}$ $\Rightarrow (x+d)^2 = 2 x^2$ $\Rightarrow (x+d) = \pm \sqrt2 x$ $\Rightarrow x = \frac{d}{\sqrt2 -1} $
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