Area bounded by the curves \(y=\sqrt{x},x=2y+3\) in the first quadrant and \(x-\) axis is1\(2\sqrt{3}\)2\(18\)3\(9\)4\(\frac{34}{3}\)Answer & explanation+Correct answer: option 3\(\begin{aligned}\text{Area}&=\int_{0}^{3}(2y+3-y^{2})dy\\ &=9\end{aligned}\)
