Assuming earth to be a sphere of a uniform density, what is the value of gravitational acceleration in a mine 100 km below the earth's surface (Given R = 6400km) :
Answer & explanation
Correct answer: option 1
Acceleration due to gravity at depth d :
\(g' = g(1 - \frac{d}{R})\)
\(g' = 9.8(1 - \frac{1}{64})\)
\(g' = g(\frac{63}{64})\) = 9.66 m/s2