A refrigerator works between 0°C and 30°C. It is required to remove 700 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is : (Take 1 cal = 4.2 Joules)
Answer & explanation
Correct answer: option 4
COP of a refrigerator is given by
COP = $ \frac{Q_c}{W} = \frac{T_c}{T_h - T_c}$
$\Rightarrow W = Q_c \frac{T_h - T_c}{T_c} = 700\times 4.2 \frac{30}{273} = 323W$