Practicing Success
The point of intersection the lines $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\frac{x-4}{5}=\frac{y-1}{2} = z$, is : |
(1, 1, 1) (1, -1, -1) (-1, 1, -1) (-1, -1, -1) |
(-1, -1, -1) |
$l_1: \frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ $l_2 : \frac{x-4}{5}=\frac{y-1}{2} = z$ Let $l_2 : \frac{x-4}{5} = \frac{y-1}{2} = z = λ$ so z = λ y = 2λ + 1 x = 5λ+4 putting value in $l_1$ $\frac{5λ+4-1}{2} = \frac{2λ+1-2}{3}=\frac{λ-3}{4}$ ⇒ $\frac{5λ+3}{2} = \frac{2λ-1}{3}=\frac{λ-3}{4}$ comparing any two we get $\frac{2λ - 1}{3} = \frac{λ - 3}{4}$ ⇒ 8λ - 4 = 3λ - 9 ⇒ 5λ = -5 ⇒ λ = -1 so x = 5(-1) + 4 = -1 y = 2(-1) + 1 = -1 z = -1 (-1, -1, -1) |