Ratio of free electron density to hole density of a p-type semiconductor is
Answer & explanation
Correct answer: option 2
In p-type semiconductors,holes are the majority carrier ,
so nh > ne
∴ \(\frac{n_e}{n_h} < 1 \)
Ratio of free electron density to hole density of a p-type semiconductor is
Correct answer: option 2
In p-type semiconductors,holes are the majority carrier ,
so nh > ne
∴ \(\frac{n_e}{n_h} < 1 \)