Practicing Success
Practicing Success
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If (1+tan2θ)(1+(tan2θ)-1) = K then \(\sqrt {K}\) = ? |
Sinθ sec θ cosecθ secθ cosecθ cosθ sin θ cosθ |
cosecθ secθ |
Put θ = 45° (1+1)(1+1) = K K =4, \(\sqrt {K}\) = 2 Take opt. B cosecθ secθ = \(\sqrt {2}\) × \(\sqrt {K}\) = 2 |
