Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Index Numbers and Time Based Data

Question:

Two varieties of coffee worth ₹124 per kg and ₹130 per kg are mixed with a third variety in the ratio 1 : 1: 2. If the mixture is worth ₹150 per kg, then the price (in ₹) of the third variety is :

Options:

346

148

254

173

Correct Answer:

173

Explanation:

The correct answer is Option (4) → 173

The cost of mixture is given by,

$\frac{(124×1)+(130×1)+(x×2)}{1+1+2}=150$

$\frac{124+130+2x}{4}=150$

$⇒2x=346$

$⇒x=173$