A number is decreased by 20 % to get another number. The number so obtained is increased by 200 % to get a third number. The difference of the third number and the original number is what percentage more or less than the difference of second and the third number?

Less, 12.5 Percent

Let the first number = 100

According to the question,

The second number = 80 ( 20% less than first number)

Third number is 200% of the second number = 80 × 300% = 240

The difference between third and the first = 240 - 100 = 140

The difference between the second and the third  = 240 - 80 = 160

Percentage % = ( 160  - 140) × \(\frac{100}{160}\) = (20) × \(\frac{100}{160}\) = Less, 12.5 Percent