A number is decreased by 20 % to get another number. The number so obtained is increased by 200 % to get a third number. The difference of the third number and the original number is what percentage more or less than the difference of second and the third number?
Answer & explanation
Correct answer: option 4
Let the first number = 100
According to the question,
The second number = 80 ( 20% less than first number)
Third number is 200% of the second number = 80 × 300% = 240
The difference between third and the first = 240 - 100 = 140
The difference between the second and the third = 240 - 80 = 160
Percentage % = ( 160 - 140) × \(\frac{100}{160}\) = (20) × \(\frac{100}{160}\) = Less, 12.5 Percent