Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

The population of a town increases by 8% every year. If the present population of the town is 14,580, then what was the population of the town 2 years ago?

Options:

13,600

12,200

13,765

12,500

Correct Answer:

12,500

Explanation:

Initial Population= x

population after 3 years = 14,580

According to question ,

x × \(\frac{108}{100}\) × \(\frac{108}{100}\)  = 14580

x = 14580 × \(\frac{25}{27}\) × \(\frac{25}{27}\)

= 12500

Population of town before 2 years is 12500.