Match the type of hybridisation given in List-I with their geometry given in List-II

Choose the correct answer from the options given below:

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

The correct answer is Option (4) → (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

The correct answer is Option (4) → (A)-(IV), (B)-(III), (C)-(I), (D)-(II).

Reasoning:
Geometry depends on the number of hybrid orbitals (steric number) formed around the central atom.

(A) sp³
sp³ means 1s + 3p = 4 hybrid orbitals → arrange to minimize repulsion → tetrahedral geometry → (IV)

(B) dsp²
dsp² means 1d + 1s + 2p = 4 hybrid orbitals arranged in one plane → square planar geometry → (III)

(C) sp³d
sp³d means 1s + 3p + 1d = 5 hybrid orbitals → trigonal bipyramidal geometry → (I)

(D) sp³d²
sp³d² means 1s + 3p + 2d = 6 hybrid orbitals → octahedral geometry → (II)

Quick memory trick:

• 4 orbitals → tetrahedral

• 4 (with d involvement, planar) → square planar

• 5 orbitals → trigonal bipyramidal

• 6 orbitals → octahedral

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