What is the smallest number which leaves remainder 3 when divided by any of the numbers 5, 6 or 8, but leaves no remainder when it is divided by 9?
Answer & explanation
Correct answer: option 2
LCM(5, 6, 8)
⇒ LCM = 240
⇒ required number = 240 + 3
⇒ 243
243 is also divisible by 9
∴ 243 is the least number divided by 5, 6, 8 gives remainder 3.