In the given figure, cos θ is equal to:

$\frac{5}{13}$ $\frac{12}{13}$ $\frac{5}{12}$ $\frac{12}{5}$

$\frac{5}{13}$

By observing the triangle PQR carefully . we find that B = 12 & H = 13 By using pythagoras theorem , P² + B² = H² P² + 12² = 13² P² = 169 - 144 P² = 25 P = 5 cosθ = \(\frac{B}{H}\) = \(\frac{5}{13}\)  { in case angle is θ , B = 5 }