After an accident, a train moves at \(\frac{2}{3}\) of its original speed and due to this it reaches 45 minutes late. What is the original time of journey?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 90 minutes
For the same distance, time is inversely proportional to speed: at \(\frac{2}{3}\) of the speed, the journey takes \(\frac{3}{2}\) of the time.
Let the original time be t minutes; the slower journey takes \(\frac{3}{2}t\)
The delay is \(\frac{3}{2}t-t=\frac{1}{2}t=45\)
\(t=90\) minutes