After an accident a train moves at $\frac{2}{3}$ of its original speed and due to this it reaches 45 minute late. What is the original time of journey?
Answer & explanation
Correct answer: option 3
Let the speed of the train = 3x
After accident it travels with = 2/3 × 3x = 2x
so, if the distance is same then the speed is inversely proportional to the time,
So, Speed = 3x : 2x
Time will be = 2x : 3x
So, extra time = 3x - 2x = x
x = 45 min
So, the original time = 45 × 2 = 90min