A galvanometer has a resistance of 8 Ω. It is shunted by a wire of resistance 2 Ω. If the total current is 2 A, the current passing through the shunt is

1.6 A

The correct answer is Option (1) → 1.6 A

$R_g = 8,\; R_s = 2,\; I = 2$

$I_s = I \cdot \frac{R_g}{R_g + R_s}$

$I_s = 2 \cdot \frac{8}{8 + 2}$

$I_s = 2 \cdot \frac{8}{10}$

$I_s = \frac{16}{10} = 1.6$

Final Answer: $1.6\ \text{A}$