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If a2 + b2 + c2 + 27 = 6 (a + b + c) then, \(\frac{a^3 + b^3 - c^3}{3}\) is? |
3 6 9 27 |
9 |
a2 + b2 + c2 + 27 = 2 (3a + 3b + 3c) We can directly conclude from ↑ a = 3, b = 3, c = 3 Hence, \(\frac{a^3 + b^3 - c^3}{3}\) = \(\frac{27 + 27 - 27}{3}\) = 9 |
