A box contains 10 mangoes out of which 4 are rotten. Two mangoes are taken out together. If one of them is found to be good, then find the probability that the other is also good.

$\frac{5}{13}$

A → other is good

B → one is good

$P(A/B)=\frac{P(A∩B)}{P(B)}$

$P(A∩B)=\frac{{^6C}_2}{{^{10}C}_2}$

$P(B)=\frac{{^{10}C}_2-{^4C}_2}{{^{10}C}_2}∴P(A/B)=\frac{5}{13}$