When $U^{235}$ is bombarded with one neutron, the fission occurs and the products are three neutrons, ${ }_{36} \mathrm{Kr}^{94}$ and
Answer & explanation
Correct answer: option 2
${ }_0 n^1+{ }_{92} U^{235} \rightarrow{ }_{36} K r^{94}+{ }_{56} B a^{139}+3{ }_0 n^1$