The number of C-Cl bonds (carbon being sp2 hybridized) in D.D.T is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 2
The hybridisation of a carbon atom depends on the bonds it forms. A carbon in a benzene ring is sp2 hybridised, while a carbon with four single bonds is sp3 hybridised. So a chlorine on a benzene ring (aryl halide) is bonded to an sp2 carbon, and a chlorine on an alkyl carbon to an sp3 carbon.
DDT is p,p′-dichlorodiphenyltrichloroethane, IUPAC name 1,1,1-trichloro-2,2-bis(4-chlorophenyl)ethane:
\( \displaystyle \ce{(Cl-C6H4)2CH-CCl3} \)
It has five C–Cl bonds:
One chlorine on each of the two benzene rings: 2 C–Cl bonds with sp2 carbon.
Three chlorines on the CCl3 carbon: 3 C–Cl bonds with sp3 carbon.
So the number of C–Cl bonds with an sp2 carbon in DDT is 2.
NCERT (2026-27 edition):
DDT
