If $x^3 + 27 y^3 + 64z^3 = 36 xyz$, then the relationship between x, y and z is

x + y + z = 0 x - 3y + 4z = 0 x + 3y = 4z x + 3y + 4z = 0

x + 3y + 4z = 0

We know that, If a + b + c = 0 then a3 + b3 + c3 = 3abc x3 + 27y3 + 64z3 = 36xyz x3 + (3y)3 + (4z)3 = 3 × (x) × (3y) × (4z) = x + 3y + 4z = 0