What is the oxidation number of Cr in [Cr(NH3)4Cl2]+ complex?

+4 +3 +2 +6

+3

Oxidation number of Cr in [Cr(NH3)4Cl2]+ is  x +4(0) + 2(-1) = 1 x - 2 = 3 x = 1+2 = 3