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Chemistry
Inorganic: Coordination Compounds
What is the oxidation number of Cr in [Cr(NH3)4Cl2]+ complex?
+4
+3
+2
+6
Oxidation number of Cr in [Cr(NH3)4Cl2]+ is
x +4(0) + 2(-1) = 1
x - 2 = 3
x = 1+2 = 3