What is the oxidation number of Cr in [Cr(NH3)4Cl2]+ complex?
Answer & explanation
Correct answer: option 2
Oxidation number of Cr in [Cr(NH3)4Cl2]+ is
x +4(0) + 2(-1) = 1
x - 2 = 3
x = 1+2 = 3
What is the oxidation number of Cr in [Cr(NH3)4Cl2]+ complex?
Correct answer: option 2
Oxidation number of Cr in [Cr(NH3)4Cl2]+ is
x +4(0) + 2(-1) = 1
x - 2 = 3
x = 1+2 = 3