Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Linear Programming

Question:

Consider the LPP

Min $Z=x-y,$ subject to the conditions

$x+y ≤3,$

$y-x ≥ 1,$

$x≥0, y≥ 0,$ then minimum value of objective function exists at the point :

Options:

(0, 3)

(3, 0)

(1, 2)

(2, 1)

Correct Answer:

(0, 3)

Explanation:

$Z=x-y$, $x+y ≤3,$ $y-x ≥ 1$

Solving $x+y=3$

$y-x=1$

we get, $x=1,y=2$

points →  (0, 1)   (0, 3 )  (1, 2) 
Z value→ -1 -3 -1

min. value at (0, 3)