In photoelectric effect, the stopping potential depends on the |
intensity of the incident radiation Frequency of the incident radiation only nature of the material only frequency of the incident radiation and nature of material both |
frequency of the incident radiation and nature of material both |
The correct answer is Option (4) → frequency of the incident radiation and nature of material both Explanation: In photoelectric effect, stopping potential $V_0 = \frac{h\nu - \phi}{e}$ depends on the frequency $\nu$ of incident radiation and the work function $\phi$ (nature of the material), but not on intensity. |