The sides of a rectangular field are in the ratio 3: 4 and its area is 7500 m2. What is the cost of fencing it at 25 paise per meter?
Answer & explanation
Correct answer: option 1
Area of the rectangle = length x breadth
7500 = 3y x 4y
7500 = 12y2
y2 = \(\frac{7500}{12 }\)
y2= 625
y = 25
thus, sides are: 25 x 3 = 75 cm and 25 x 4 = 100 cm
In order to know the cost of fencing, we need to know the perimeter of the field i.e. 2(l + b)
2(l + b) = 2(75 + 100) = 175 x 2 = 350
Cost of fencing = 350 x 0.25 = Rs. 87.5