A triangle ABC is inscribed in a circle with center O. AO is produced to meet the circle at K and AO is angle bisector of A. AD ⊥ BC. If ∠B = 70° and ∠C = 54°, then the measure of ∠DAK is.
Answer & explanation
Correct answer: option 2
∠DAK = \(\frac{∠B-∠C}{2}\) = \(\frac{70°-54°}{2}\) = \(\frac{16}{2}\) = 8°