CUET Preparation Today
The self-inductance of an inductance coil having 100 turns is 20 mH. The total flux through the coil for a current of 4 mA is: |
$8 × 10^{-5} Wb$ $4 × 10^{-3} Wb$ $8 × 10^{-4} Wb$ $4 × 10^{-4} Wb$ |
$8 × 10^{-5} Wb$ |
The correct answer is Option 1: $8 × 10^{-5} Wb$
Note: This question was dropped by NTA as none of the given options was correct. So, in order to provide additional practice to the students, we have modified one option so that there is one correct answer. |
