Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Calculus

Question:

If $y=57e^{6x}+39e^{-6x}$ then $\frac{d^2y}{dx^2}$ is equal to :

Options:

342y

$6y^2$

$36y$

$234y^2$

Correct Answer:

$36y$

Explanation:

The correct answer is Option (3) → $36y$

$y=57e^{6x}+39e^{-6x}$

$\frac{dy}{dx}=57e^{6x}×6+39e^{-6x}×-6$

$⇒\frac{d^2y}{dx^2}=57e^{6x}×36+39e^{-6x}×36$

$=36(57e^{6x}+39e^{-6x})$

$=36y$