The slope of the tangent to the curve $y = –x^3 + 3x^2 + 9x – 27$ is maximum when x equals
Answer & explanation
Correct answer: option 1
If m be the slope of the tangent to the given curve, then
$m = = – 3x^2 + 6x + 9$
$= – 6x + 6, = – 6$
Now $= 0 – 6x + 6 = 0 x = 1$
$= – 6 < 0 $
so at x = 1 the slope m will be maximum