Practicing Success
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Which of the transitions in hydrogen atom emits a photon of lowest frequency (n = quantum number) |
n = 2 to n = 1 n = 4 to n = 3 n = 3 to n = 1 n = 4 to n = 2 |
n = 4 to n = 3 |
From diagram
$E_1=-13.6-(-3.4)=-10.2 eV$ $E_2=-13.6-(-1.51)=-12.09 eV$ $E_3=-1.51-(-0.85)=-0.66 eV$ $E_4=-3.4-(-1.51)=-1.89 eV$ $E_3$ is least i.e. frequency is lowest. |
