An object is placed at 5 cm distance in

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Target Exam

CUET

Subject

Physics

Chapter

Ray Optics

Question:

An object is placed at 5 cm distance in front of concave mirror of radius of curvature 15 cm. Find the position of image.

Options:

20 cm

7.5 cm

15 cm

40 cm

Correct Answer:

15 cm

Explanation:

f = R/2 = 15/2 cm

u = -5 cm , f = -7.5 cm

$\Rightarrow \frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{-2}{15} - \frac{-1}{5} = \frac{1}{15}$

$\Rightarrow v = 15cm$