An object is placed at 5 cm distance in front of concave mirror of radius of curvature 15 cm. Find the position of image.
Answer & explanation
Correct answer: option 3
f = R/2 = 15/2 cm
u = -5 cm , f = -7.5 cm
$\Rightarrow \frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{-2}{15} - \frac{-1}{5} = \frac{1}{15}$
$\Rightarrow v = 15cm$