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An object is placed at 5 cm distance in front of concave mirror of radius of curvature 15 cm. Find the position of image. |
20 cm 7.5 cm 15 cm 40 cm |
15 cm |
f = R/2 = 15/2 cm u = -5 cm , f = -7.5 cm $\Rightarrow \frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{-2}{15} - \frac{-1}{5} = \frac{1}{15}$ $\Rightarrow v = 15cm$ |
