In the given figure, AP is perpendicular to BC and AQ is bisector of angle PAC.  What will be the measure of angle PQA?

25° 45° 55° 65°

65°

In triangle APC ∠P = 90°, ∠C = 40° So, ∠PAC = 180° - (90° + 40°) = 50° ∠PAQ = \(\frac{1}{2}\) ∠PAC = \(\frac{50°}{2}\) = 25° In triangle APQ ⇒ ∠Q = 180° - (∠P + ∠A) = 180° - (90° + 25°) = 65°