In the given figure, AP is perpendicular to BC and AQ is bisector of angle PAC. What will be the measure of angle PQA?
Answer & explanation
Correct answer: option 4
In triangle APC
∠P = 90°, ∠C = 40°
So, ∠PAC = 180° - (90° + 40°) = 50°
∠PAQ = \(\frac{1}{2}\) ∠PAC = \(\frac{50°}{2}\) = 25°
In triangle APQ
⇒ ∠Q = 180° - (∠P + ∠A) = 180° - (90° + 25°) = 65°