Practicing Success
Practicing Success
CUET Preparation Today
If A is a singular matrix, then adj A is |
non-singular singular symmetric not defined |
singular |
We have, $|A| = 0$. Let A be a square matrix of order n. Then, $|adj\, A|=|A|^{n-1}$ $⇒|adj\, A|= 0$ $⇒adj\, A$ is a singular matrix. |
