The price of diesel is increased by 26%. A person wants to increase his expenditure by 15% only. By what percentage, correct to one decimal place, should he decrease his consumption?

8.7 %

26% = \(\frac{13}{50}\)

15% = \(\frac{3}{20}\)

ATQ,

Price             ⇒  50  :   63

Consumption ⇒   a   :    b

Expenditure   ⇒  20  :    23

{Price × consumption = Expenditure}

Now,

⇒ \(\frac{50a}{63b}\) = \(\frac{20}{23}\)

⇒ \(\frac{a}{b}\) = \(\frac{126}{115}\)

⇒  Consumption decreased by = 126 - 115 = 11

⇒ Decreased percentage = \(\frac{11}{126}\) × 100 = 8.7%