What is the molarity of 9.8% (w/w) H2SO4 solution (density = 1.02 g/ml)?
Answer & explanation
Correct answer: option 1
9.8 g of H2SO4 is dissolved in 100 g of solution. (9.8% w/w)
Molecular mass of H2SO4 = 2x1 + 32 + 4x16 = 2+32+64 = 98g
no of moles = \(\frac{9.8}{98}\) = \(\frac{98}{980}\) = \(\frac{1}{10}\) = 0.1
density = \(\frac{mass}{volume}\)
1.02 = \(\frac{100}{volume}\)
Volume = \(\frac{100}{1.02}\) = \(\frac{10000}{102}\)ml
M = \(\frac{0.1}{\frac{10000}{102}}\)x1000 = 1.02 M