What is the molarity of 9.8% (w/w) H₂SO₄ solution (density = 1.02 g/ml)?

1.02 M

9.8 g of H₂SO₄ is dissolved in 100 g of solution. (9.8% w/w)

Molecular mass of H₂SO₄ = 2x1 + 32 + 4x16 = 2+32+64 = 98g

no of moles = \(\frac{9.8}{98}\) = \(\frac{98}{980}\) = \(\frac{1}{10}\) = 0.1

density = \(\frac{mass}{volume}\)

1.02 = \(\frac{100}{volume}\)

Volume = \(\frac{100}{1.02}\) = \(\frac{10000}{102}\)ml

M = \(\frac{0.1}{\frac{10000}{102}}\)x1000 = 1.02 M