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If $y=6x+\frac{4}{x}$ then $\frac{d^2y}{dx^2}$ at $x=2$ is : |
-1 -2 2 1 |
1 |
The correct answer is Option (4) → 1 $y=6x+\frac{4}{x}$ $⇒\frac{dy}{dx}=6-\frac{4}{x^2}$ $⇒\frac{d^2y}{dx^2}=\frac{4×2}{x^2}=\frac{8}{x^2}$ $\left.\frac{d^2y}{dx^2}\right|_{x=2}=\frac{8}{8}=1$ |
