Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Indefinite Integration

Question:

find the integral \(\int\frac{( { x }^{ 2 } - 3x + 2)}{x-1}dx\)

Options:

\[ \frac{ { x }^{ 2 } }{2} -2x+c\]

\[ \frac{ {- x }^{ 2 } }{2} -2x+c\]

\[ \frac{ { x }^{ 2 } }{2} + 2x+c\]

\[ \frac{ {- x }^{ 2 } }{2} +2x+c\]

Correct Answer:

\[ \frac{ { x }^{ 2 } }{2} -2x+c\]

Explanation:

\[\int x dx = \frac{ { x }^{ 2 } }{2}+c\]