What is $\frac{dy}{dx}$ if $x^2+xy+y^2=100$
Answer & explanation
Correct answer: option 2
$x^2+xy+y^2=100$
differentiating wrt x
$2x+y+x\frac{dy}{dx}+2y\frac{dy}{dx}=0$
so $\frac{dy}{dx}=\frac{-2x-y}{x+2y}$
What is $\frac{dy}{dx}$ if $x^2+xy+y^2=100$
Correct answer: option 2
$x^2+xy+y^2=100$
differentiating wrt x
$2x+y+x\frac{dy}{dx}+2y\frac{dy}{dx}=0$
so $\frac{dy}{dx}=\frac{-2x-y}{x+2y}$