What is $\frac{dy}{dx}$ if $x^2+xy+y^2=100$ |
$\frac{2x+y}{x+y}$ $\frac{-2x-y}{x+2y}$ $\frac{x+2y}{x+y}$ $\frac{x-y}{x+y}$ |
$\frac{-2x-y}{x+2y}$ |
$x^2+xy+y^2=100$ differentiating wrt x $2x+y+x\frac{dy}{dx}+2y\frac{dy}{dx}=0$ so $\frac{dy}{dx}=\frac{-2x-y}{x+2y}$ |