Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

The ratio of the radius of gyration of a thin uniform disc about an axis passing through its centre and normal to its plane to the radius of gyration of the disc about its diameter is : 

Options:

2 : 1

1 : \(\sqrt{2}\)

4 : 1

\(\sqrt{2}\) : 1

Correct Answer:

\(\sqrt{2}\) : 1

Explanation:

 

I1 = MR2 / 2

k1 = \(\sqrt{\frac{I_1}{M}}\) = \(\frac{R}{sqrt{2}}\)

I2 = MR2 / 4

k2 = \(\sqrt{\frac{I_2}{M}}\) = \(\frac{R}{2}\)

k1 : k2\(\sqrt{2}\) : 1