Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

Options:

a

b

c

d

Correct Answer:

d

Explanation:

$\text{Energy radiated by electron when jump from n=2 to n=1 is } \Delta E = 10.2eV$

For $He^+ , E_1 = -54.4 eV , E_2 = -13.6eV , E_3 = -6.04eV , E_4 = -3.4eV$

Hence for He+, Transition will be from n=2 to n= 4.