The value of \(\left(\frac{x}{y}\right)^{2a-3b}\times\left(\frac{x}{y}\right)^{3b-4c}\times\left(\frac{x}{y}\right)^{4c-2a}\)
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 1
Powers of the same base are multiplied by adding the exponents: \(a^{m}\times a^{n}\times a^{p}=a^{m+n+p}\). Any non-zero number raised to the power 0 is 1.
Sum of the exponents: \((2a-3b)+(3b-4c)+(4c-2a)=0\)
The product \(\displaystyle =\left(\frac{x}{y}\right)^{0}=1\)