Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Chemical Bonding and Molecular Structure

Question:

Match the property given in List I with the molecule given in List II.

List I List II
A. Zero dipole moment, non-polar bonds i. \(BF_3\)
B. Zero dipole moment polar bonds ii. \(O_2\)
C. Molecule with higher dipole moment iii. \(CHCl_3\)
D. Molecule having lower dipole moment iv. \(CH_3Cl\)

Choose the correct answer from the options given below:

Options:

A-i, B-ii, C-iii, D-iv

A-ii, B-i, C-iv, D-iii

A-iv, B-iii, C-ii, D-i

A-i, B-ii, C-iv, D-iii

Correct Answer:

A-ii, B-i, C-iv, D-iii

Explanation:

The correct answer is option 2. A-ii, B-i, C-iv, D-iii.

List I List II
A. Zero dipole moment, non-polar bonds ii. \(O_2\)
B. Zero dipole moment polar bonds i. \(BF_3\)
C. Molecule with higher dipole moment iv. \(CH_3Cl\)
D. Molecule having lower dipole moment iii. \(CHCl_3\)


Now, let's analyze each molecule and its corresponding property:

(i) \(BF_3\):

\(BF_3\) (Boron trifluoride) has polar covalent bonds between boron and fluorine atoms. Despite having polar bonds, \(BF_3\) has a trigonal planar geometry where the dipole moments of the bonds cancel each other out, resulting in a molecule with a zero dipole moment. Therefore, (i) \(BF_3\) matches with property (B) Zero dipole moment, polar bonds.

(ii) \(O_2\):

\(O_2\) (Oxygen gas) consists of a diatomic molecule with a non-polar covalent double bond between the two oxygen atoms. This non-polar nature leads to \(O_2\) having a zero dipole moment. Therefore, (ii) \(O_2\) matches with property (A) Zero dipole moment, non-polar bonds.

(iii) \(CHCl_3\):

\(CHCl_3\) (Chloroform) has polar covalent bonds between carbon and hydrogen/chlorine atoms. The molecular structure of \(CHCl_3\) is tetrahedral with one hydrogen and three chlorine atoms bonded to the central carbon atom. The dipole moments of these bonds do not cancel each other perfectly due to the asymmetric distribution of atoms around the central carbon atom, resulting in a higher dipole moment. Therefore, (iii) \(CHCl_3\) matches with property (C) Molecule with higher dipole moment.

(iv) \(CH_3Cl\):

\(CH_3Cl\) (Chloromethane) also has polar covalent bonds between carbon and hydrogen/chlorine atoms. However, the molecular structure of \(CH_3Cl\) is tetrahedral with one hydrogen and one chlorine atom bonded to the central carbon atom. The symmetry of \(CH_3Cl\) results in a more balanced cancellation of dipole moments compared to CHCl3, leading to a lower dipole moment. Therefore, (iv) \(CH_3Cl\) matches with property (D) Molecule with lower dipole moment.

Conclusion:
Based on the analysis above, the correct matching between List I and List II is:

(A) matches with (ii) \(O_2\) (Zero dipole moment, non-polar bonds)

(B) matches with (i) \(BF_3\) (Zero dipole moment, polar bonds)

(C) matches with (iii) \(CHCl_3\) (Molecule with higher dipole moment)

(D) matches with (iv) \(CH_3Cl\) (Molecule with lower dipole moment)