Sixteen men can finish a work in 8 days. Eight men and nine women working together can finish the same work in 10 days. In how many days will twenty women finish the same work?
Answer & explanation
Correct answer: option 2
Given,
16M x 8 = (8M + 9W) x 10
⇒ 64M = 40M + 45W
⇒ 24M = 45W
⇒ M : W = 45 : 24 = 15 : 8 (Efficiency)
⇒ Total work = 16 (15) x 8 = 1920 units. ..(Efficiency × Days = Total work)
⇒ Time required by 20 women to complete the work = \(\frac{1920}{20(8)}\) = \(\frac{1920}{160}\) = 12 days. ..(\(\frac{Work}{Efficiency}\) = Time)