The domain of the function $sin^{-1}(4x-1)$ is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $[0, \frac{1}{2}]$
from definition
$-1≤4x-1≤1$
$0≤4x≤2$
$0≤x≤\frac{1}{2}$
$⇒x∈[0,\frac{1}{2}]$
The domain of the function $sin^{-1}(4x-1)$ is :
Correct answer: option 3
The correct answer is Option (3) → $[0, \frac{1}{2}]$
from definition
$-1≤4x-1≤1$
$0≤4x≤2$
$0≤x≤\frac{1}{2}$
$⇒x∈[0,\frac{1}{2}]$