CUET Preparation Today
The order and degree of the differential equation $x\left(\frac{dy}{dx}\right)^3+\left(\frac{d^2y}{dx^2}\right)^2-3\frac{dy}{dx}+y=0$ respectively, are |
2 and 3 3 and 2 2 and 1 2 and 2 |
2 and 2 |
The correct answer is Option (4) → 2 and 2 order = $\frac{d^2y}{dx^2}$ ⇒ order = 2 degree of $\left(\frac{d^2y}{dx^2}\right)$ ⇒ degree = 2 |
