The principal value of $\cos^{-1} \left( \frac{1}{2} \right) + \sin^{-1} \left( -\frac{1}{\sqrt{2}} \right)$ is: |
$\frac{\pi}{12}$ $\pi$ $\frac{\pi}{3}$ $\frac{\pi}{6}$ |
$\frac{\pi}{12}$ |
The correct answer is Option (1) → $\frac{\pi}{12}$ ## $\cos^{-1} \left( \frac{1}{2} \right) + \sin^{-1} \left( -\frac{1}{\sqrt{2}} \right)$ $= \cos^{-1} \left( \cos \frac{\pi}{3} \right) - \sin^{-1} \left( \frac{1}{\sqrt{2}} \right)$ [Since $\sin^{-1}(-\theta) = -\sin^{-1} \theta$] $= \frac{\pi}{3} - \sin^{-1} \left( \sin \frac{\pi}{4} \right) = \frac{\pi}{3} - \frac{\pi}{4} = \frac{\pi}{12}$ |