CUET Preparation Today
Match List-I with List-II
Choose the correct answer from the options given below: |
(A)-(III), (B)-(II), (C)-(IV), (D)-(I) (A)-(III), (B)-(II), (C)-(I), (D)-(IV) (A)-(IV), (B)-(I), (C)-(III), (D)-(II) (A)-(I), (B)-(IV), (C)-(II), (D)-(III) |
(A)-(III), (B)-(II), (C)-(IV), (D)-(I) |
The correct answer is Option (1) → (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
Match by reading symmetric form $(x-x_0)/a=(y-y_0)/b=(z-z_0)/c$ so point is $(x_0,y_0,z_0)$ and direction ratios are $(a,b,c)$. (I) $\frac{x+3}{5}=\frac{y+7}{-4}=\frac{z+2}{6}\Rightarrow$ point $(-3,-7,-2)$, direction ratios $(5,-4,6)$. (II) $\frac{x-3}{5}=\frac{y-7}{-4}=\frac{z-2}{6}\Rightarrow$ point $(3,7,2)$, direction ratios $(5,-4,6)$. (III) $\frac{x-5}{3}=\frac{y+4}{7}=\frac{z-6}{2}\Rightarrow$ point $(5,-4,6)$, direction ratios $(3,7,2)$. (IV) $\frac{x+5}{3}=\frac{y-4}{7}=\frac{z+6}{2}\Rightarrow$ point $(-5,4,-6)$, direction ratios $(3,7,2)$. |
